Class 11 Chemistry Chapter 4 Chemical Bonding and Molecular Structure MCQs

Class 11 chemistry MCQs with answers are provided here for chapter 4 Chemical Bonding and Molecular Structure. These MCQs are based on CBSE board curriculum and correspond to the most recent Class 11 chemistry syllabus. By practicing these Class 11 Multiple choice questions, students will be able to quickly review all of the ideas covered in the chapter and prepare for the Class 11 Annual examinations as well as other entrance exams such as NEET and JEE.

Download Chapter 4 Chemical Bonding and Molecular Structure MCQs PDF by clicking on the button below.
Download PDF

Class 12 Chemical Bonding and Molecular Structure MCQs

1. Which one of them is the weakest?

(b) Covalent bond

(c) Metallic Bond

(d) van der Waals force

Solution: Among them van der Waals force is the weakest force.

2. The bond angle around atom which uses sp 2 hybridization is ———–

Solution: The bond angle around an atom which uses sp 2 hybridization is 120 0 .

3. In the resonating structures of benzene, the number of sigma and pi bonds are

Solution: In Benzene (C6H6) ring contain 3 alternative double bond = 3π bonds and (six C-C sigma bond + six C-H sigma bond) = 12 σ bonds

4. Which of the following substances has a dipole moment more than zero?

(c) Carbon dioxide

Solutions: The dipole moment (μ) of H₂O = 1.84 D

5. The ion which is iso-electronic with CO is —————

Solution : Both CO (6 + 8=14) and CN – (6 + 7+1= 14) have the same electrons. so they are iso-electronic with each other.

6. The correct bond order in the following species is —————.

Solution: The correct one is O₂ – < O₂ + < O₂ 2+ , bond order is 1.5 < 2.5 < 3.0 respectively.

7. Which of the following molecules have trigonal planar geometry?

Solution: BF₃ has trigonal planar geometry. The hybridization of BF₃ is sp 2 hybridization.

8. During change of O₂ to O₂ 2- ion, the electron adds on which of the following orbitals?

Solution: The incoming electrons added to π* orbital in the change of O₂ to O₂ 2- ion.

9. In which of the following pairs, the two molecules have identical bond orders:

Solution: Both N₂ and O₂ 2+ have bond order equal to 3.0.

10. Ionic bonds will be formed more easily between elements with comparatively:

(a) low ionization enthalpy and high electron affinity

(b) high ionization enthalpy and high electron affinity

(c) low ionization enthalpy and low electron affinity

(d) high ionization enthalpy and low electron affinity

Solution: Ionic bonds will be formed more easily between elements with low ionization enthalpy and high electron affinity.